C\u00e1ch \u0111\u00e1nh \u0111\u1ec1 theo t\u1ed5ng c\u1ee7a d\u00e2n ch\u01a1i chuy\u00ean nghi\u1ec7p c\u00f3 g\u00ec kh\u00e1c so v\u1edbi c\u00e1ch \u0111\u00e1nh \u0111\u1ec1 t\u1ed5ng th\u00f4ng th\u01b0\u1eddng. Theo c\u00e1c chuy\u00ean gia ch\u01a1i l\u00f4 \u0111\u1ec1 online l\u00e2u n\u0103m v\u1eabn th\u01b0\u1eddng ng\u00e1n ng\u1ea9m khi nh\u1eafc \u0111\u1ebfn chuy\u1ec7n \u0111\u00e1nh \u0111\u1ec1 theo t\u1ed5ng. Th\u1ebf nh\u01b0ng n\u1ebfu n\u1eafm b\u1eaft \u0111\u01b0\u1ee3c c\u00e1ch \u0111\u00e1nh theo t\u1ed5ng th\u00ec ch\u1eafc ch\u1eafn b\u1ea1n s\u1ebd c\u1ea3m th\u1ea5y \u0111\u00e1nh \u0111\u1ec1 theo l\u1ed1i n\u00e0y r\u1ea5t hi\u1ec7u qu\u1ea3.<\/p>\n
N\u1ed9i dung:<\/p>\n
- \n
- 1<\/span>\u00a0C\u00e1ch \u0111\u00e1nh \u0111\u1ec1 theo t\u1ed5ng l\u00e0 g\u00ec?<\/li>\n
- 2<\/span>\u00a0Ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i t\u1ed5ng \u0111\u1ec1\n
- \n
- 2.1<\/span>\u00a0Ch\u01a1i t\u1ed5ng \u0111\u1ec1 d\u1ef1a v\u00e0o b\u1ea1c nh\u1edb l\u00f4 \u0111\u1ec1<\/li>\n
- 2.2<\/span>\u00a0Kinh nghi\u1ec7m ch\u01a1i t\u1ed5ng \u0111\u1ec1 theo t\u1ed5ng \u0111\u1ec1 trong tu\u1ea7n<\/li>\n
- 2.3<\/span>\u00a0C\u00e1ch ch\u01a1i t\u1ed5ng \u0111\u1ec1 d\u1ef1a v\u00e0o gi\u1ea3i \u0111\u1eb7c bi\u1ec7t<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/div>\n
C\u00e1ch \u0111\u00e1nh \u0111\u1ec1 theo t\u1ed5ng l\u00e0 g\u00ec?<\/span><\/h2>\n
C\u00e1ch \u0111\u00e1nh \u0111\u1ec1 theo t\u1ed5ng hay c\u00f2n g\u1ecdi l\u00e0 t\u1ed5ng \u0111\u1ec1 \u0111\u01b0\u1ee3c hi\u1ec3u \u0111\u01a1n gi\u1ea3n l\u00e0 t\u1ed5ng c\u1ee7a 2 s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ed9ng v\u1edbi nhau r\u1ed3i l\u1ea5y t\u1ed5ng theo h\u00e0ng \u0111\u01a1n v\u1ecb. T\u1eeb c\u00e1ch n\u00e0y ta s\u1ebd c\u00f3 t\u1ea5t c\u1ea3 10 t\u1ed5ng t\u01b0\u01a1ng \u1ee9ng v\u1edbi 10 s\u1ed1 t\u1eeb 0 \u0111\u1ebfn 9 c\u1ee7a d\u00e3y s\u1ed1 t\u1ef1 nhi\u00ean.<\/p>\n
V\u00ed d\u1ee5: Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t XSMB ng\u00e0y 3\/11\/2024 l\u00e0:\u00a040911<\/strong><\/p>\n
Ta l\u1ea5y t\u1ed5ng 2 s\u1ed1 cu\u1ed1i \u0111\u01b0\u1ee3c t\u1ed5ng \u0111\u1ec1 h\u00f4m \u0111\u00f3 l\u00e0 1 + 1 = 2<\/p>\n
\u0110\u1ec3 ch\u01a1i \u0111\u01b0\u1ee3c c\u00e1ch \u0111\u00e1nh \u0111\u1ec1 theo t\u1ed5ng n\u00e0y b\u1ea1n c\u1ea7n ph\u1ea3i th\u01b0\u1eddng xuy\u00ean theo d\u00f5i k\u1ebft qu\u1ea3 \u0111\u1ec3 ch\u1ecdn cho m\u00ecnh \u0111\u01b0\u1ee3c b\u1ed9 t\u1ed5ng ch\u00ednh x\u00e1c v\u00e0 th\u1ef1c hi\u1ec7n theo ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i t\u1ed5ng \u0111\u1ec1 d\u01b0\u1edbi \u0111\u00e2y.<\/p>\n
Ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i t\u1ed5ng \u0111\u1ec1<\/span><\/h2>\n
- 2.2<\/span>\u00a0Kinh nghi\u1ec7m ch\u01a1i t\u1ed5ng \u0111\u1ec1 theo t\u1ed5ng \u0111\u1ec1 trong tu\u1ea7n<\/li>\n
- 2<\/span>\u00a0Ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i t\u1ed5ng \u0111\u1ec1\n